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X^2-13X=180
We move all terms to the left:
X^2-13X-(180)=0
a = 1; b = -13; c = -180;
Δ = b2-4ac
Δ = -132-4·1·(-180)
Δ = 889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{889}}{2*1}=\frac{13-\sqrt{889}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{889}}{2*1}=\frac{13+\sqrt{889}}{2} $
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